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MathGroup Archive 2000

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Re: powersum with a function with variable count of parameters

  • To: mathgroup at smc.vnet.net
  • Subject: [mg25273] Re: [mg25262] powersum with a function with variable count of parameters
  • From: Richard Palmer <mapsinc at bellatlantic.net>
  • Date: Sun, 17 Sep 2000 17:33:39 -0400 (EDT)
  • Sender: owner-wri-mathgroup at wolfram.com

on 9/17/00 4:47 AM, Klamser at Klamser at t-online.de wrote:

> Hi,
> 
> how can I write a function f[x_,xi__]=10^x+10^xi, that returns
> f[1,2,3]->10^1+10^2+10 ^3.
> 
> When i use the above definition, I only get
> 
> 10^1+10^2^3
> 
> But I want to get
> 
> 10^1+10^2+10 ^3
> 
> Regrads, Peter
> 
> 
> 
Try PowerSum[args__]:=Plus@@{10^#&/@List[args])

The args parameter has two (2) underscores following it.  This permits 1 or
more arguments.  List[args] turns the arguments into a list.  the function
10^# is mapped onto each element of the list (creating another list) and the
elements of the list are finally summed.

Regards,  Richard Palmer



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