Re: Question
- To: mathgroup at smc.vnet.net
- Subject: [mg25271] Re: [mg25258] Question
- From: BobHanlon at aol.com
- Date: Sun, 17 Sep 2000 17:33:38 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
In a message dated 9/17/2000 4:54:38 AM, smitsky at mindspring.com writes:
>Hi, can anyone be so kind as to tell me how this problem:
>
>1/cbrt(m) +2 (One over the Cube Root of "m" plus Two)
>
>...can be solved in Mathematica by rationalizing the denominator? Thank
>you.
>
f[m_] := 1/Rationalize[N[m^(1/3)], 0] + 2;
Table[f[m], {m, 10}]
{3, 818099381/292837179, 160180721/59472423,
261314795/99360729, 319745309/123701977,
400834502/157170203, 315222994/124951739, 5/2,
342055810/137884039, 435566974/176760913}
If the 2 was actually intended to be be part of the denominator then
g[m_] := 1/(Rationalize[N[m^(1/3)], 0] + 2);
Table[g[m], {m, 10}]
{1/3, 232425023/757687225, 41235875/141944173,
62593337/224547403, 72341355/268384687,
86494096/330158395, 65319516/255590771, 1/4,
66287732/270459503, 82045148/340851209}
Bob Hanlon