Re: Question

*To*: mathgroup at smc.vnet.net*Subject*: [mg25271] Re: [mg25258] Question*From*: BobHanlon at aol.com*Date*: Sun, 17 Sep 2000 17:33:38 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

In a message dated 9/17/2000 4:54:38 AM, smitsky at mindspring.com writes: >Hi, can anyone be so kind as to tell me how this problem: > >1/cbrt(m) +2 (One over the Cube Root of "m" plus Two) > >...can be solved in Mathematica by rationalizing the denominator? Thank >you. > f[m_] := 1/Rationalize[N[m^(1/3)], 0] + 2; Table[f[m], {m, 10}] {3, 818099381/292837179, 160180721/59472423, 261314795/99360729, 319745309/123701977, 400834502/157170203, 315222994/124951739, 5/2, 342055810/137884039, 435566974/176760913} If the 2 was actually intended to be be part of the denominator then g[m_] := 1/(Rationalize[N[m^(1/3)], 0] + 2); Table[g[m], {m, 10}] {1/3, 232425023/757687225, 41235875/141944173, 62593337/224547403, 72341355/268384687, 86494096/330158395, 65319516/255590771, 1/4, 66287732/270459503, 82045148/340851209} Bob Hanlon