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Re:"serie"


At arbitary k this Sum is a function of complex argument:

S = 1/2*(1 + Pi*Coth[Pi] - 
I*(HarmonicNumber[-I + k] - HarmonicNumber[I + k])) 

With k->Infinity

S -> 1/2*(1 + Pi*Coth[Pi])=
2.076674047468581174134050794750000490446.

Zak

%%%%%%%%%%%%%%%%%%%%%%%%%5


Subject: [mg30216]      serie
Author:       Ahmet Mutlu <ahmet at ata.cs.hun.edu.tr>
Organization: Steven M. Christensen and Associates, Inc and
MathTensor, Inc.

hi
what is the sum

for i:=1 to k
    total = total + 1/(i^2 + 1)


i mean, a formal sum.



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