Re: using findroot for multiple functions

*To*: mathgroup at smc.vnet.net*Subject*: [mg30360] Re: [mg30337] using findroot for multiple functions*From*: Andrzej Kozlowski <andrzej at tuins.ac.jp>*Date*: Sun, 12 Aug 2001 02:29:50 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

The most obvious way seems to be just: In[1]:= t /.FindRoot[(t-#)*Sin[t+#] + Sin[t-#]*Cos[t+#], {t,0}]&/@{1, 3.4, 99.1,100, 109} Out[1]= {1.,-0.147548,7.71714,0.539788,0.946994} On Saturday, August 11, 2001, at 04:39 PM, Amy Sommer wrote: > I need to solve multiple equations varying one parameter. I am able to > do > this if I vary the parameter in equal steps, but I have a list of > numbers > that I need to plug in. Here is an example because my description > probably is not very clear: > > Here is an example of what works: > > Table[t /.FindRoot[(t-a)*Sin[t+a] + Sin[t-a]*Cos[t+a], > {t,0}],[a,1,10,.5] > > My problem comes in because I want have a list of values that are not in > equal steps. I have tried the following with no success: > > list = {1, 3.4, 99.1,100,109} > ReplaceAll[[FindRoot[(t-a)*Sin[t+a] + Sin[t-a]*Cos[t+a],{t,0}],a-> list] > > If anyone has an idea on how I can get this to work, please let me know. > > Thanks, > Amy Sommer > > > Andrzej Kozlowski Toyama International University JAPAN http://platon.c.u-tokyo.ac.jp/andrzej/