RE: using findroot for multiple functions

*To*: mathgroup at smc.vnet.net*Subject*: [mg30361] RE: [mg30337] using findroot for multiple functions*From*: "David Park" <djmp at earthlink.net>*Date*: Sun, 12 Aug 2001 02:29:50 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

Amy, A good place to use a pure function. We Map the FindRoot function onto an arbitrary list of values. t /. FindRoot[(t - #)*Sin[t + #] + Sin[t - #]*Cos[t + #], {t, 0}] & /@ {1, 3, 7.5, 8, 8.1, 9} {1., 0.0700271, -4.29968, 1.37411, 1.24612, 0.344576} David Park djmp at earthlink.net http://home.earthlink.net/~djmp/ > From: Amy Sommer [mailto:amsommer at pacific.mps.ohio-state.edu] To: mathgroup at smc.vnet.net > > I need to solve multiple equations varying one parameter. I am able to do > this if I vary the parameter in equal steps, but I have a list of numbers > that I need to plug in. Here is an example because my description > probably is not very clear: > > Here is an example of what works: > > Table[t /.FindRoot[(t-a)*Sin[t+a] + Sin[t-a]*Cos[t+a], {t,0}],[a,1,10,.5] > > My problem comes in because I want have a list of values that are not in > equal steps. I have tried the following with no success: > > list = {1, 3.4, 99.1,100,109} > ReplaceAll[[FindRoot[(t-a)*Sin[t+a] + Sin[t-a]*Cos[t+a],{t,0}],a-> list] > > If anyone has an idea on how I can get this to work, please let me know. > > Thanks, > Amy Sommer > >