Re: Integration of "Which" function

*To*: mathgroup at smc.vnet.net*Subject*: [mg32109] Re: [mg32100] Integration of "Which" function*From*: BobHanlon at aol.com*Date*: Thu, 27 Dec 2001 03:34:10 -0500 (EST)*Sender*: owner-wri-mathgroup at wolfram.com

In a message dated 12/25/01 12:04:20 AM, klepachd at yahoo.com writes: >I am trying to integrate : >Integrate[Which[0 <= x <= 1/2, 0, 1/2 < x <= 1, 2], {x, 0, 1}] > Your function is essentially the UnitStep function Clear[f]; f[x_] := 2*UnitStep[x-1/2]; However, f gives a different value at x = 1/2 f[1/2] 2 Assuming that the value at this point matters, this can be fixed with a separate definition for x = 1/2 f[1/2] = 0; Integrate[f[x], {x, 0, 1}] 1 Plot[{f[x], Integrate[f[t], {t, 0, x}]}, {x, 0, 1}]; Bob Hanlon Chantilly, VA USA