Mathematica 9 is now available
Services & Resources / Wolfram Forums
-----
 /
MathGroup Archive
2001
*January
*February
*March
*April
*May
*June
*July
*August
*September
*October
*November
*December
*Archive Index
*Ask about this page
*Print this page
*Give us feedback
*Sign up for the Wolfram Insider

MathGroup Archive 2001

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Meaning of @ ... not @@

  • To: mathgroup at smc.vnet.net
  • Subject: [mg32159] Re: [mg32152] Meaning of @ ... not @@
  • From: Andrzej Kozlowski <andrzej at tuins.ac.jp>
  • Date: Sun, 30 Dec 2001 02:54:24 -0500 (EST)
  • Sender: owner-wri-mathgroup at wolfram.com

All you need to do to find out the answer is evaluate:

In[72]:=
f@x

Out[72]=
f[x]

Andrzej


P.S. Your instructions for sending e-mai to your address are far too 
complicated and I doubt many people will feel generous enough to make 
the effort needed to decode them. I don't.

Andrzej Kozlowski
Toyama International University
JAPAN
http://platon.c.u-tokyo.ac.jp/andrzej/

On Sunday, December 30, 2001, at 08:00  AM, DIAMOND Mark R. wrote:

> I'm sure I've seen this before, but cannot find the answer on the 
> archive
> because I can't think of a sensible way of limiting the search!
>
> What, please, is the meaning of @ as in
> Conjugate @ Reverse @ Drop[list, -1]
>
> I seem to remember reading that this was "undocumented", and I cannot 
> find
> it in the help. The above line appears in mg1432 in the archive.
>
> --
> Mark R. Diamond
> Send email to  server called psy dot uwa dot edu dot au and address to 
> markd
> http://www.psy.uwa.edu.au/user/markd
>
>
>
>
>



  • Prev by Date: RE: Meaning of @ ... not @@
  • Next by Date: Re: Searching for embedded zeros in list
  • Previous by thread: RE: Meaning of @ ... not @@
  • Next by thread: Re: Meaning of @ ... not @@