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MathGroup Archive 2001

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AW: Contour Plot

  • To: mathgroup at smc.vnet.net
  • Subject: [mg27116] AW: [mg26984] Contour Plot
  • From: "Wolf, Hartmut" <Hartmut.Wolf at t-systems.de>
  • Date: Sun, 4 Feb 2001 02:58:50 -0500 (EST)
  • Sender: owner-wri-mathgroup at wolfram.com


-----Ursprüngliche Nachricht-----
Von: Roberto Ruiz de Austri [mailto:r.ruizdeaustri at lancaster.ac.uk]
Gesendet: Mittwoch, 31. Januar 2001 05:22
An: mathgroup at smc.vnet.net
Betreff: [mg26984] Contour Plot


 Dear MathGroup Reader,

   I have a data file including differents physical quantities (e.g. x,
y, z1, z2, ....in differents columns) . I generate shaded contour plots
  for each "zi". After that I try to link these figures in one with
"Show[ figure1,figure2,... ]" sentences. But I just get the first in the
list.
  What is the way to get just one figure including all "zi".


  Thank you very much.


  Roberto.



Dear Roberto,

let's look at these Plots:

sc = ContourPlot[Sin[x y/2], {x, -5, 5}, {y, -5, 5}, ContourShading ->
False, 
      Contours -> 7, ContourStyle -> RGBColor[1, 0, 0], PlotPoints -> 50];
ss = ContourPlot[Sin[x y/2], {x, -5, 5}, {y, -5, 5}, ContourLines -> False, 
      Contours -> 7, PlotPoints -> 50];
cc = ContourPlot[Sin[(x^2 + y^2)/4.], {x, -5, 5}, {y, -5, 5}, 
      ContourShading -> False, Contours -> 7, 
      ContourStyle -> RGBColor[0, 0, 1], PlotPoints -> 50];
cs = ContourPlot[Sin[(x^2 + y^2)/4.], {x, -5, 5}, {y, -5, 5}, 
      ContourLines -> False, Contours -> 7, PlotPoints -> 50];

Show[{sc, cc}];

If you have no contour shading the graphical objects only contain the lines
which clearly superpose in the resultant combined graphics.

Show[{ss, cs}];

With contour shading the second graphic completely shadows the first. The
reason is that the shades contours are represented by (filled) Polygones.

Show[{ss, cc}];

This in some circumstance might be an acceptable compromise (contour shading
for the first graphic, with superimposed contour lines)

-- Hartmut Wolf



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