Re: Q: Factor with Polynominals?

*To*: mathgroup at smc.vnet.net*Subject*: [mg26985] Re: Q: Factor with Polynominals?*From*: Robert <robert.schuerhuber at gmx.at>*Date*: Tue, 30 Jan 2001 23:22:10 -0500 (EST)*Organization*: Vienna University of Technology*References*: <943d4e$chm@smc.vnet.net> <9461cq$gaa@smc.vnet.net> <948rc8$kku@smc.vnet.net> <94gqbh$qsj@smc.vnet.net> <dOJb6.6098$nn4.155772@ralph.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

thanks again for your answers! unfortunately your method works with the (rather simple) examples, but it fails with longer, more complex poynomials. robert Allan Hayes wrote: > Here is a technique that works, with little thought, for both of the > examples given so far in this thread. > > poly = (x^2 + y^2)^4 + y (x^2 + y^2) + y; > poly2 = 3 x^2 + 3 y^2 + x + y^3 + y x^2; > > tf[u___ + a_ b_ + v___ + a_ c_ + w___] := u + a(b + c) + v + w; > tf[z_] := z; > > fs = FullSimplify[poly, TransformationFunctions -> {Automatic, tf}, > ComplexityFunction -> (Length[#] &) > ]