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Re: Unevaluated Expression
*To*: mathgroup at smc.vnet.net
*Subject*: [mg26989] Re: Unevaluated Expression
*From*: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
*Date*: Tue, 30 Jan 2001 23:22:12 -0500 (EST)
*Organization*: Universitaet Leipzig
*References*: <955v6k$1i@smc.vnet.net>
*Sender*: owner-wri-mathgroup at wolfram.com
Hermann Meier wrote:
>
> Dear Mathematica users,
>
> a = 10;
> Unprotect[ToString]; SetAttributes[ToString, HoldAll]
> ToString[a]//FullForm
> gives (as desired) "a", not 10
>
> Then I wanted to prevent the argument in f[x_] := x^2 from
> getting evaluated.
>
> Attributes[f] = {HoldAll}
> f[x_] := x^2
> f[Unevaluated[a]]
> gives 100.
If you don't want, that f[] gets evaluated why do you define
rules for the evaluation ???
The definition:
SetAttributes[f, HoldAll]
f[x_Symbol] := (Print["huhu"]; x^2)
f[x_?NumericQ] := x^2
and
f[a]
will Print[] "huhu" because a is left unevaluated (due to the
attribute) and the a_Symbol pattern matches.
While
g[x_Symbol] := (Print["huhu1"]; x^2)
g[x_?NumericQ] := x^2
and g[a] will a evaluate to 10 and use the second rule and no "huhu1"
is printed.
>
> The longwinded code
> ToExpression[ToString[f[a]], InputForm, Hold] /. Hold[f[nr_]] -> nr
> or
> First[Level[Composition[Hold][f[#]],{-1}]]& /@ {a,10}
>
> at least manages to give 10 instead of 100.
>
> Is there really no way to prevent the argument in f[x] from firing ?
The argument isn't firing the right hand side of the rule
f[x_]:=
will replace your argument.
you don't want that f[] is evaluated instead of an unevaluated argument.
And Hold[f[a]] will work
Regards
Jens
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