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Re: a problem with differentiation


On Tue, 3 Jul 2001, Soh Pek Hooi wrote:
Hello

you could try the following:
h[t_] := 2t^2
v[h_] := 4/2(h^3 + 4h^2)

D[v[h], h]

   2*(8*h + 3*h^2)

saludos
carlos


> Hi,
>
> If I have
> h= 2t^2
> v = 4/2(h^3+4h^2)
>
> How do I evaluate D[v,h] in terms of h without having h to be substituted in
> the following manner?
>
> Function[{h,v}, D[v, h]][2t^2, 4/2(h^3+4h^2)]
>
> Will appreciate your comments.
>
> Pek
>
>



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