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Re: a problem with differentiation

  • To: mathgroup at
  • Subject: [mg29707] Re: a problem with differentiation
  • From: "Orestis Vantzos" <atelesforos at>
  • Date: Wed, 4 Jul 2001 03:08:31 -0400 (EDT)
  • Organization: National Technical University of Athens, Greece
  • References: <9hs0sk$br6$>
  • Sender: owner-wri-mathgroup at

Define h=2t^2 but v:=4/2(h^3+4h^2)
The SetDelayed in the definition of v should not disturb your code.
It does allows this though:

Block[{h = H}, Function[{H}, D[v, h] // Evaluate]]
Function[{H}, 2(8 H + 3 H^2)]

The result is a pure Function, which eliminates the problem of h
spontaneously evaluating into 2t^2.

"Soh Pek Hooi" <fbasohph at> wrote in message
news:9hs0sk$br6$1 at
> Hi,
> If I have
> h= 2t^2
> v = 4/2(h^3+4h^2)
> How do I evaluate D[v,h] in terms of h without having h to be substituted
> the following manner?
> Function[{h,v}, D[v, h]][2t^2, 4/2(h^3+4h^2)]
> Will appreciate your comments.
> Pek

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