Re: Partitioning 1-D list into 2-D Matrix
- To: mathgroup at smc.vnet.net
- Subject: [mg29780] Re: Partitioning 1-D list into 2-D Matrix
- From: "Orestis Vantzos" <atelesforos at hotmail.com>
- Date: Sun, 8 Jul 2001 20:35:55 -0400 (EDT)
- Organization: National Technical University of Athens, Greece
- References: <9i6ao4$ol6$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Why use Partition 2 times!?! Partition[b,5] returns the matrix you want. Generaly a single application of Partition to a vector will return a (rectangular) matrix. As a second argument to Partition you can supply any divisor of the Length of the vector. Orestis "Krautschik, Chris G" <krautschikc at intel.co.jp> > > b=Range[1,20] > {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20} > > I would like to arrange the list into a 2D array of the following form: > {{1, 3, 5, 7, 9}, {2, 4, 6, 8, 10}, {11, 13, 15, 17, 19}, {12, 14, 16, 18, > 20}} > > Then > bb=Partition[Partition[b,2],5] > <<...OLE_Obj...>> > almost does what I want if you view this array in MatrixForm[]. However, I > would have to somehow get rid of the innner brackets. I am not sure how to > do that with Flatten[]. > > I could use brute force and select the elements as follows: > <<...OLE_Obj...>> > <<...OLE_Obj...>> > > I have a feeling there is a much better way to do this. > > Thanks in advance, > Chris > >