Integrate[Sqrt[Tan[x]], {x, 0, 1}]
- To: mathgroup at smc.vnet.net
- Subject: [mg30130] Integrate[Sqrt[Tan[x]], {x, 0, 1}]
- From: seidov at yahoo.com (Zakir F. Seidov)
- Date: Sun, 29 Jul 2001 21:26:21 -0400 (EDT)
- Organization: The Math Forum
- References: <9j8nqi$5qf$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
After some manipulations this integral is: (2*(Pi + ArcTan[Sqrt[2*Tan[1]]/(1 - Tan[1])])+ Log[(Tan[1] - Sqrt[2*Tan[1]] + 1)/ (Tan[1] + Sqrt[2*Tan[1]] + 1)])/(2*Sqrt[2]), or 0.7272982493435106435530636987436355542425 Enjoy! Zakir %%%%%%%%%%%%%%%%%%%%%%%%% Subject: [mg30130] Integrate[Sqrt[Tan[x]], {x, 0, 1}] -- approx ?? Author: Tim 9-23 <bendoftimeb at stny.rr.com> Organization: Steven M. Christensen and Associates, Inc and MathTensor, Inc. How do I just get the approx. of this, say 5 decimal places? Mathematica gives an exact answer which is in terms of multiple fractions, roots, and complex numbers. According to my TI-85, it is approx. 0.7273 My email address is anti-spammed. Remove the 2 B's after hitting email reply if you want to email me. Tim 9-23