Integrate[Sqrt[Tan[x]], {x, 0, 1}]

• To: mathgroup at smc.vnet.net
• Subject: [mg30130] Integrate[Sqrt[Tan[x]], {x, 0, 1}]
• From: seidov at yahoo.com (Zakir F. Seidov)
• Date: Sun, 29 Jul 2001 21:26:21 -0400 (EDT)
• Organization: The Math Forum
• References: <9j8nqi\$5qf\$1@smc.vnet.net>
• Sender: owner-wri-mathgroup at wolfram.com

```After some manipulations this integral is:

(2*(Pi + ArcTan[Sqrt[2*Tan[1]]/(1 - Tan[1])])+
Log[(Tan[1] - Sqrt[2*Tan[1]] + 1)/
(Tan[1] + Sqrt[2*Tan[1]] + 1)])/(2*Sqrt[2]), or

0.7272982493435106435530636987436355542425

Enjoy!

Zakir

%%%%%%%%%%%%%%%%%%%%%%%%%

Subject: [mg30130]      Integrate[Sqrt[Tan[x]], {x, 0, 1}]  --  approx ??
Author:       Tim 9-23 <bendoftimeb at stny.rr.com>
Organization: Steven M. Christensen and Associates, Inc and
MathTensor, Inc.

How do I just get the approx. of this, say 5 decimal places?
Mathematica gives an exact answer which is in terms of multiple
fractions, roots, and complex numbers.

According to my TI-85, it is approx. 0.7273

My email address is anti-spammed.  Remove the 2 B's after hitting
email reply
if you want to email me.

Tim 9-23

```

• Prev by Date: Re: Filename as Function Argument"
• Next by Date: Re: A Penny for Thought
• Previous by thread: Re: Filename as Function Argument"
• Next by thread: Integrate[Sqrt[Tan[x]], {x, 0, 1}]