Re: log x > x - proof?
- To: mathgroup at smc.vnet.net
- Subject: [mg28133] Re: [mg28049] log x > x - proof?
- From: "Mark Harder" <harderm at ucs.orst.edu>
- Date: Sat, 31 Mar 2001 02:59:02 -0500 (EST)
- Sender: owner-wri-mathgroup at wolfram.com
Joe,
The statement log[x]>x for ALL x>0 is obviously false, by
counterexample:
Let x=1, then log[x]=0 and 0<1, not 0>1!!!
Are you sure there isn't a misprint in your message?
-mark harder
harderm at ucs.orst.edu
-----Original Message-----
From: Joe <sorry at no.email>
To: mathgroup at smc.vnet.net
Subject: [mg28133] [mg28049] log x > x - proof?
>Dear all,
>
>Please could someone give me some hints as to how to prove that
>
>log x > x for all x > 0
>
>Isn't it proof by contradiction, or by intimidation?
>
>Thanks in advance,
>
>Joe
>
>
>