Re: Please help!

*To*: mathgroup at smc.vnet.net*Subject*: [mg28658] Re: [mg28649] Please help!*From*: BobHanlon at aol.com*Date*: Sat, 5 May 2001 04:00:43 -0400 (EDT)*Sender*: owner-wri-mathgroup at wolfram.com

You cannot have a pattern (T_0) in the Integral Y = Integrate[Exp[-T^2/(2T0^2)]Exp[iwT], {T, -Infinity, Infinity}, Assumptions -> T0 > 0] E^iwT*Sqrt[2*Pi]*T0 Integrate[Y*Exp[beta2*w^2*z-iwT],{w,-Infinity,Infinity}, Assumptions -> beta2*z < 0] (Sqrt[2]*Pi*T0)/Sqrt[(-beta2)*z] Bob Hanlon In a message dated 2001/5/4 12:37:23 AM, rex_chaos at 263.net writes: >I wonder why I can't get the analytic form of the following integration >by Mathematica: > In[1] = Y=Integrate[Exp[-T^2/(2T_0^2)]Exp[iwT], {T, -Infinity, > Infinity}] > In[2] = Integrate[YExp[beta2*w^2*z-iwT],{w,-Infinity,Infinity}] > Unforunately, the anwser given by Mathematica is the orginal formula > I input. > Would you please give me a hand? >