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Re: Please help!

  • To: mathgroup at smc.vnet.net
  • Subject: [mg28658] Re: [mg28649] Please help!
  • From: BobHanlon at aol.com
  • Date: Sat, 5 May 2001 04:00:43 -0400 (EDT)
  • Sender: owner-wri-mathgroup at wolfram.com

You cannot have a pattern (T_0) in the Integral

Y = Integrate[Exp[-T^2/(2T0^2)]Exp[iwT], {T, -Infinity,
  Infinity}, Assumptions -> T0 > 0]

E^iwT*Sqrt[2*Pi]*T0

Integrate[Y*Exp[beta2*w^2*z-iwT],{w,-Infinity,Infinity}, 
  Assumptions -> beta2*z < 0] 

(Sqrt[2]*Pi*T0)/Sqrt[(-beta2)*z]


Bob Hanlon

In a message dated 2001/5/4 12:37:23 AM, rex_chaos at 263.net writes:

>I wonder why I can't get the analytic form of the following integration
>by Mathematica:
>  In[1] = Y=Integrate[Exp[-T^2/(2T_0^2)]Exp[iwT], {T, -Infinity,
>  Infinity}]
>  In[2] = Integrate[YExp[beta2*w^2*z-iwT],{w,-Infinity,Infinity}]
>  Unforunately, the anwser given by Mathematica is the orginal formula
>  I input.
>  Would you please give me a hand?
>


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