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Inverse Laplace output format?


I have the following inverse Laplace -

f = (11s^2 + 172s + 700)/((s + 2)(s^2 + 12s + 100))
InverseLaplaceTransform[f, s, t]

but the answer is in exponential form.

I understand the ExpToTrig command but I want to get the
answer in "cos theta in degree" form -

5Exp[-2t] + 10Exp[-6t]cos(8t - 53.13°)

How do I do that because when I use the ExpToTrig I get

(3 - 4 \[ImaginaryI]) Cosh[(6 + 8 \[ImaginaryI]) t] - (3 - 4 \[ImaginaryI])
Sinh[(6 + 8 \[ImaginaryI]) t]

and don't know what to do to get it to my "cos theta in degree" form.






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