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Re: help! - questions about Integration
*To*: mathgroup at smc.vnet.net
*Subject*: [mg28856] Re: help! - questions about Integration
*From*: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
*Date*: Wed, 16 May 2001 03:28:05 -0400 (EDT)
*Organization*: Universitaet Leipzig
*References*: <9dqdvp$4jv@smc.vnet.net>
*Sender*: owner-wri-mathgroup at wolfram.com
Hi,
I expect serious typing errors in your equation
A < (x^2+y^2)/(x^2 Y^2 x^2-y^2) < B
it may be
A < (x^2+y^2)/(x^4 Y^2-y^2) < B
or
A < (x^2+y^2)/(x^2 y^2+ x^2-y^2) < B
With Mathematica 4.1 *and* the correct formula you may try
Needs["Calculus`Integration`"]
Integrate[
Exp[-(x/a)^2 - (y/b)^2]*
Boole[A < (x^2 + y^2)/(x^2 y^2+ x^2 - y^2) < B],
{x, -Infinity, Infinity},
{y, -Infinity, Infinity}]
How ever your inequality does not work.
Regards
Jens
c6wang at sciborg.uwaterloo.ca wrote:
>
> Hello! I am quite new about Mathematica, can someone help me out this
> question?
>
> I want to do an integration, as written below:
>
> Integrate[Exp[-(x/a)^2-(y/b)^2], x and y are variables (-Infinity,
> Infinity),
> integration area is defined by
> A < (x^2+y^2)/(x^2 Y^2 x^2-y^2) < B,
>
> Where a, b, A, B are invariables.
>
> I am wondering if Mathematica can find out a way to to this. Or there is a
> function from Mathematica special for this kind of integration?
>
> Thank you in advance!
>
> Regards
>
> Connie
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