MathGroup Archive 2001

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: help! - questions about Integration

  • To: mathgroup at
  • Subject: [mg28856] Re: help! - questions about Integration
  • From: Jens-Peer Kuska <kuska at>
  • Date: Wed, 16 May 2001 03:28:05 -0400 (EDT)
  • Organization: Universitaet Leipzig
  • References: <9dqdvp$>
  • Sender: owner-wri-mathgroup at


I expect serious typing errors in your equation

A < (x^2+y^2)/(x^2 Y^2 x^2-y^2) < B

it may be
A < (x^2+y^2)/(x^4 Y^2-y^2) < B

A < (x^2+y^2)/(x^2 y^2+ x^2-y^2) < B

With Mathematica 4.1 *and* the correct formula you may try


    Exp[-(x/a)^2 - (y/b)^2]*
      Boole[A < (x^2 + y^2)/(x^2 y^2+ x^2 - y^2) < B], 
     {x, -Infinity, Infinity}, 
     {y, -Infinity, Infinity}]

How ever your inequality does not work.


c6wang at wrote:
> Hello! I am quite new about Mathematica, can someone help me out this
> question?
> I want to do an integration, as written below:
> Integrate[Exp[-(x/a)^2-(y/b)^2],  x and y are variables (-Infinity,
> Infinity),
> integration area is defined by
> A < (x^2+y^2)/(x^2 Y^2 x^2-y^2) < B,
> Where a, b, A, B are invariables.
> I am wondering if Mathematica can find out a way to to this. Or there is a
> function from Mathematica special for this kind of integration?
> Thank you in advance!
> Regards
> Connie

  • Prev by Date: Re: Plotting different function with different Plotstyle in one graph
  • Next by Date: Re: Creating graph with only a view data points
  • Previous by thread: help! - questions about Integration
  • Next by thread: webMathematica Hosting Service