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Re: help! - questions about Integration

  • To: mathgroup at smc.vnet.net
  • Subject: [mg28856] Re: help! - questions about Integration
  • From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
  • Date: Wed, 16 May 2001 03:28:05 -0400 (EDT)
  • Organization: Universitaet Leipzig
  • References: <9dqdvp$4jv@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Hi,

I expect serious typing errors in your equation

A < (x^2+y^2)/(x^2 Y^2 x^2-y^2) < B

it may be
A < (x^2+y^2)/(x^4 Y^2-y^2) < B

or
A < (x^2+y^2)/(x^2 y^2+ x^2-y^2) < B

With Mathematica 4.1 *and* the correct formula you may try

Needs["Calculus`Integration`"]

  Integrate[
    Exp[-(x/a)^2 - (y/b)^2]*
      Boole[A < (x^2 + y^2)/(x^2 y^2+ x^2 - y^2) < B], 
     {x, -Infinity, Infinity}, 
     {y, -Infinity, Infinity}]

How ever your inequality does not work.

Regards
  Jens


c6wang at sciborg.uwaterloo.ca wrote:
> 
> Hello! I am quite new about Mathematica, can someone help me out this
> question?
> 
> I want to do an integration, as written below:
> 
> Integrate[Exp[-(x/a)^2-(y/b)^2],  x and y are variables (-Infinity,
> Infinity),
> integration area is defined by
> A < (x^2+y^2)/(x^2 Y^2 x^2-y^2) < B,
> 
> Where a, b, A, B are invariables.
> 
> I am wondering if Mathematica can find out a way to to this. Or there is a
> function from Mathematica special for this kind of integration?
> 
> Thank you in advance!
> 
> Regards
> 
> Connie


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