MathGroup Archive 2001

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Creating graph with only a view data points

  • To: mathgroup at smc.vnet.net
  • Subject: [mg28991] Re: Creating graph with only a view data points
  • From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
  • Date: Thu, 24 May 2001 04:07:09 -0400 (EDT)
  • Organization: Universitaet Leipzig
  • References: <9dqdf2$4j7@smc.vnet.net> <9dta7t$f60@smc.vnet.net> <ogFN6.9155$dl4.27332@ralph.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Hi,

you must make two parametric functions 
x[t] and y[t]


makeParmetricInterpolation[data:{_,_}]:=
  Module[{n=Length[data]-1,tlist},
    tlist=MapIndexed[{First[#2-1]/n,#1} &,data];
    {Interpolation[tlist /. {t_?NumericQ,x_,_}:> {t,x}],
     Interpolation[tlist /. {t_?NumericQ,_,y_}:> {t,y}]}
   ]

and now you can draw a parametric curve with t in [0,1]

Regards
  Jens

Oliver Tonn wrote:
> 
> First of all thanks for your help.
> I'm sorry, but your solution don't work in my case.
> It could happen, that I have to go back on the x and y axis.
> For example:
> 
> {{0,0},{1,0.5},{2,0.5},{3,0.5},{2.1,1.5},{1,5}}
> 
> Mathematica isn't realy happy with that.
> 
> Do you, or anybody else, have a solution for that?
> 
> Greetings Oliver


  • Prev by Date: Re: Help fitting Exponential curves
  • Next by Date: Re: Q: Extract Elements from a List?
  • Previous by thread: Re: Re: Creating graph with only a view data points
  • Next by thread: help! - questions about Integration