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MathGroup Archive 2001

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Re: Congruences

  • To: mathgroup at smc.vnet.net
  • Subject: [mg29025] Re: [mg29007] Congruences
  • From: "Milton Brown" <miltbrown at earthlink.net>
  • Date: Fri, 25 May 2001 01:48:00 -0400 (EDT)
  • References: <200105240807.EAA05001@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

19 x = 1 mod 40  solution is  x = 59

x = 12 mod 16  solution is  x = 12

I have a program I can provide if you are interested.

Milton L. Brown
miltbrown at earthlink.net


----- Original Message -----
From: "Flip" <nospam at newsranger.com>
To: mathgroup at smc.vnet.net
Subject: [mg29025] [mg29007] Congruences


> Hi All,
>
> I was having a difficult time find this in the documentation and was
hoping
> someone here could help.
>
> 1.  How do you solve the congruence 19 x = 1 mod 140?
>
> 2.  I am trying to verify that x = 12 mod 16 (where x is a 1024-bit
number).
> How do I do that (essentially the same as question 1.)?
>
> Thank you ... Flip
>
>



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