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Re: A tricky equation

  • To: mathgroup at
  • Subject: [mg29015] Re: A tricky equation
  • From: Erik Schaffer <erik.schaffer at>
  • Date: Fri, 25 May 2001 01:47:53 -0400 (EDT)
  • Organization: Uni Graz
  • References: <9eihld$>
  • Sender: owner-wri-mathgroup at

Anastasius Moumtzoglou wrote:
> I would be much obliged if you could help me with the following
> equation.
> b*k^(-a)-c*k^(-1)=1
> Mathematica returns that the above equation is a transcedental one. So,
> I'm thinking of linearization. Do you think there is a way to do it?
I know the problem, afaik mathematica can't solve equations with
variables as exponents.
I had a different problem, it was a system of 4 equations with variables
as exponents, I solved it by dividing one of the equations by another
one. In this case, the exponents disappeared.

Here I don't know what to do :-(



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