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MathGroup Archive 2001

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Re: Congruences

  • To: mathgroup at smc.vnet.net
  • Subject: [mg29026] Re: [mg29007] Congruences
  • From: "Milton Brown" <miltbrown at earthlink.net>
  • Date: Fri, 25 May 2001 01:48:01 -0400 (EDT)
  • References: <200105240807.EAA05001@smc.vnet.net> <001701c11450$5422f1c0$f5e3b3d1@pams>
  • Sender: owner-wri-mathgroup at wolfram.com

Should have said

19 x = 1 mod 140  solution is  x = 59


----- Original Message ----- 
From: "Milton Brown" <miltbrown at earthlink.net>
To: mathgroup at smc.vnet.net
Subject: [mg29026] Re: [mg29007] Congruences


> 19 x = 1 mod 40  solution is  x = 59
> 
> x = 12 mod 16  solution is  x = 12
> 
> I have a program I can provide if you are interested.
> 
> Milton L. Brown
> miltbrown at earthlink.net
> 
> 
> ----- Original Message -----
> From: "Flip" <nospam at newsranger.com>
To: mathgroup at smc.vnet.net
> To: <mathgroup at smc.vnet.net>
> Sent: Thursday, May 24, 2001 1:07 AM
> Subject: [mg29026] [mg29007] Congruences
> 
> 
> > Hi All,
> >
> > I was having a difficult time find this in the documentation and was
> hoping
> > someone here could help.
> >
> > 1.  How do you solve the congruence 19 x = 1 mod 140?
> >
> > 2.  I am trying to verify that x = 12 mod 16 (where x is a 1024-bit
> number).
> > How do I do that (essentially the same as question 1.)?
> >
> > Thank you ... Flip
> >
> >
> 



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