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Re: (-8)^(1/3)


This works.

Kevin

ans = N[x /. Solve[x^3 == -8, x]]
{-2., 1. + 1.73205*I, 1. - 1.73205*I}

Select[ans, Conjugate[#1] == #1 & ]
{-2.}

"LuisMa" <nospam at newsranger.com> wrote in message
news:9rb6rm$5ch$1 at smc.vnet.net...
> When I enter
>
> (-8)^(1/3)
>
> Mathematica answer
>
> 1 + 1.73205i,
>
> but I need
>
> (-8)^(1/3) = -2
>
> How can I get it?
>
>




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