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MathGroup Archive 2001

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Re: (-8)^(1/3)

  • To: mathgroup at smc.vnet.net
  • Subject: [mg31309] Re: (-8)^(1/3)
  • From: Kevin McCann <Kevin.McCann at jhuapl.edu>
  • Date: Sat, 27 Oct 2001 01:08:20 -0400 (EDT)
  • Organization: Johns Hopkins University Applied Physics Lab, Laurel, MD, USA
  • References: <9rb6rm$5ch$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

This works.

Kevin

ans = N[x /. Solve[x^3 == -8, x]]
{-2., 1. + 1.73205*I, 1. - 1.73205*I}

Select[ans, Conjugate[#1] == #1 & ]
{-2.}

"LuisMa" <nospam at newsranger.com> wrote in message
news:9rb6rm$5ch$1 at smc.vnet.net...
> When I enter
>
> (-8)^(1/3)
>
> Mathematica answer
>
> 1 + 1.73205i,
>
> but I need
>
> (-8)^(1/3) = -2
>
> How can I get it?
>
>




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