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RE: How Do You Reduce Multiple Elements in a List?

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  • Subject: [mg33878] RE: [mg33863] How Do You Reduce Multiple Elements in a List?
  • From: "Harvey P. Dale" <hpd1 at>
  • Date: Sun, 21 Apr 2002 06:12:27 -0400 (EDT)
  • Sender: owner-wri-mathgroup at

	If the list is sorted, Split will do most of the work for you.
(Look it up in the book.)  For example:
In[1]:= {#[[1]],Length[#]}&/@Split[lstone]
Out[1]= {{1,4},{2,3},{3,6},{4,2},{5,3},{6,1}}
	If the list is not sorted, Split still does most of the work but you
should Sort the list first.  For example:
In[2]:= {#[[1]],Length[#]}&/@Split[Sort[lsttwo]]
Out[2]= {{1,2},{2,5},{3,6},{4,5},{5,3},{6,1}}
	Hope that helps.
Harvey P. Dale
University Professor of Philanthropy and the Law
Director, National Center on Philanthropy and the Law
New York University School of Law
Room 206A
110 West 3rd Street
New York, N.Y. 10012-1074
tel: 212-998-6161
fax: 212-995-3149

-----Original Message-----
From: Bob Harris [mailto:nitlion at] 
To: mathgroup at
Subject: [mg33878] [mg33863] How Do You Reduce Multiple Elements in a List?


This seems like such a simple thing, yet I've search through the big book
trying to figure it out.  Perhaps someone can help me...

Given a list of integers that generally contains the same number many times,
I'd like to reduce it to a list that just gives me the number/count pairs.
For example, I'd like to convert the list
   {1, 1, 1, 1, 1, 2, 2, 2, 4, 4, 4, 4, 4, 4}
   {{1,5}, {2,3}, (4,6}}

Is there a built-in function to do this?  Seems like a histogramming
operation, but I get no useful matches from ?*Hist*.

Bob H

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