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Re: Why these graphs differ?
*To*: mathgroup at smc.vnet.net
*Subject*: [mg33943] Re: [mg33925] Why these graphs differ?
*From*: Andrzej Kozlowski <andrzej at platon.c.u-tokyo.ac.jp>
*Date*: Wed, 24 Apr 2002 01:21:52 -0400 (EDT)
*Sender*: owner-wri-mathgroup at wolfram.com
Really it is neither. What it really means is that you should study
Mathematica a little more. The second Plot is correct while the first is
basically nonsense. What you did is make Mathematica try to solve a lot
of "differential equations" like this one:
DSolve[{Derivative[1][y][4.166666666666666*^-8] ==
4.166666666666666*^-8, y[0] == 1},
y[4.166666666666666*^-8], 4.166666666666666*^-8][[1,1, 2]]
As you can see yourself this does not make much sense. It is not a bug,
just a very basic fact about the way Plot evaluates its arguments.
Andrzej Kozlowski
Toyama International University
JAPAN
http://platon.c.u-tokyo.ac.jp/andrzej/
On Tuesday, April 23, 2002, at 08:13 PM, Vladimir Bondarenko wrote:
> These solutions, naturally, coincide.
>
> DSolve[{y'[z] == z, y[0] == 1}, y[z], z][[1, 1, 2]]
> Evaluate[DSolve[{y'[z] == z, y[0] == 1}, y[z], z][[1, 1, 2]]]
>
> (2 + z^2)/2
> (2 + z^2)/2
>
>
> But, surprisingly, the corresponding graphs are not identical:
>
> Plot[ DSolve[{y'[z] == z, y[0] == 1}, y[z], z][[1, 1, 2]], {z,
> 0, 1}]
> Plot[Evaluate[DSolve[{y'[z] == z, y[0] == 1}, y[z], z][[1, 1, 2]]], {z,
> 0, 1}]
>
>
> Is it a feature or a problem?
>
>
> Vladimir Bondarenko
>
>
>
>
>
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