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MathGroup Archive 2002

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Re: Interpolation

  • To: mathgroup at
  • Subject: [mg32309] Re: Interpolation
  • From: "Allan Hayes" <hay at>
  • Date: Sat, 12 Jan 2002 05:18:28 -0500 (EST)
  • References: <a1mbl8$2ot$>
  • Sender: owner-wri-mathgroup at

Here is an idea that might be refined:



Of course the value {0., 0.983986} is not found.


Allan Hayes
Mathematica Training and Consulting
Leicester UK
hay at
Voice: +44 (0)116 271 4198
Fax: +44 (0)870 164 0565

"Yas" <y.tesiram at> wrote in message
news:a1mbl8$2ot$1 at
> G'day mathgroup,
> I have some general questions on Interpolation as implemented in
> Mathematica. Essentially, I have a series of profiles for which I have
> no general function. The profile is generated by repetitive
> multiplication of rotation matrices and so it is difficult (and also
> impractical) to deduce an analytic function. Instead to answer the
> questions I have, I have decided to use Interpolation -- a pitiful
> state, nevertheless a shade better than extrapolation. The first step
> involves creating the Interpolating function,
> thing1 = Interpolation[data];
> Then I find the first derivative,
> thing2 = D[thing1[x], {x, 0, lastdatapoint}]
> Next I want to find the points where thing2 = 0, but I have run into
> problems with Mathematica complaining about inverse functions etc,
> although plots of thing2 versus x look fine.
> My primary question is,
> 1. The profiles that I have, have maxima and minima whose co-ordinates I
> want to find, hence the differentiation step. Interpolation does a good
> job reproducing the data points and in finding a derivative that can be
> plotted but not when asked to Solve for thing2 = 0. How do I go about
> finding the accuracy of the Interpolating Function to test whether the
> value near thing2 = 0 is well behaved?
> And a secondary question is,
> 2. Is there another efficient method of estimating the co-ordinates of
> the minima and maxima by computer of data sets?
> The length of each of these data sets is 1000 points and for that reason
> I have not pasted it into the email. As a demonstrative example, the
> Table of values generated by,
> Table[Sin[0.75 + Exp[Pi*t]], {t, 0, 1, 1/1000}];
> ListPlot[%]
> is closely related.
> Any help or comments will be appreciated.
> Thanks
> Yas

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