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Re: Absolute Value of Complex Numbers
- To: mathgroup at smc.vnet.net
- Subject: [mg35202] Re: Absolute Value of Complex Numbers
- From: "Allan Hayes" <hay at haystack.demon.co.uk>
- Date: Tue, 2 Jul 2002 02:11:55 -0400 (EDT)
- References: <afp0oh$h08$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
"Kyle Davis" <kyledavis at nowhere.com> wrote in message
news:afp0oh$h08$1 at smc.vnet.net...
> Abs[2 Exp[3 * i]]
> answer = 2
>
> Abs[2 Exp[k * i]]
> answer = 2 Exp[-Im[k]]
>
> Isn't the second answer supposed to be the same with the first one,
regardless with the value of k?
Only if k is real, but Mathematica allows for other values, for example
Abs[2 Exp[I* I]]
2/E
The general result is if k = x+I y then we get Abs[2 Exp[(x+I y)] = 2 Abs[
Exp[-y+ I x] ] = Abs[Exp[y] Exp[I x]] = Abs[Exp[-y]] = Exp[-y]]
>How do I make the second calculation give me the right answer?
Simplify[Abs[2 Exp[k * I]], Element[k, Reals]]
2
--
Allan
---------------------
Allan Hayes
Mathematica Training and Consulting
Leicester UK
www.haystack.demon.co.uk
hay at haystack.demon.co.uk
Voice: +44 (0)116 271 4198
Fax: +44 (0)870 164 0565
>
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