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MathGroup Archive 2002

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[Q] Boole Function

  • To: mathgroup at smc.vnet.net
  • Subject: [mg37206] [Q] Boole Function
  • From: Janusz Kawczak <jkawczak at math.uncc.edu>
  • Date: Wed, 16 Oct 2002 14:26:42 -0400 (EDT)
  • Sender: owner-wri-mathgroup at wolfram.com

Suppose f(x,y,z)=Boole[0<x<y<z<1]. Let's integrate this function
over, say, z, i.e. Integrate[f[x,y,z],{z,0,1}]. One would expect to see
the
output like this (1-y)Boole[0<x<y<1] (or maybe simplified expression
as an argument in  the Boole function). Instead, an error appears
(warning) that the integration cannot be performed.

How to resolve this issue so it produces a desired answer?

Janusz.


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