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AW: Strange ReplaceAll behavior
- To: mathgroup at smc.vnet.net
- Subject: [mg36802] AW: [mg36774] Strange ReplaceAll behavior
- From: Matthias.Bode at oppenheim.de
- Date: Thu, 26 Sep 2002 04:57:00 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
Hello Lawrence,
using Set (=) instead of SetDelayed (:=) in
f[x_]:=(a+b) /. ru[a];
will give you what you desire.
Best regards,
Matthias Bode.
-----Ursprüngliche Nachricht-----
Von: Lawrence A. Walker Jr. [mailto:lwalker701 at earthlink.net]
Gesendet: Mittwoch, 25. September 2002 07:51
An: mathgroup at smc.vnet.net
Betreff: [mg36774] Strange ReplaceAll behavior
Hi,
For the life of me I am not sure why the following is not working in my
v. 4.2:
ru[a]=a->x;
f[x_]:=(a+b) /. ru[a];
Why do I get
f[c] = b+x
and not
f[c] = b+c?
What gives?
Thanks,
Lawrence
--
Lawrence A. Walker Jr.
http://www.kingshonor.com
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