Re: Integrate Problem
- To: mathgroup at smc.vnet.net
- Subject: [mg40527] Re: [mg40502] Integrate Problem
- From: Dr Bob <majort at cox-internet.com>
- Date: Wed, 9 Apr 2003 01:33:22 -0400 (EDT)
- References: <200304080705.DAA23549@smc.vnet.net>
- Reply-to: majort at cox-internet.com
- Sender: owner-wri-mathgroup at wolfram.com
ComplexExpand@Integrate[1/Pi^2 1/(1 + x^2 + y^2 + z^2)^2,
{z, -Infinity, Infinity}, Assumptions -> {Im[x] == 0, Im[y] == 0, Im[z] ==
0}]
Bobby
On Tue, 8 Apr 2003 03:05:18 -0400 (EDT), Stewart Mandell
<stewart at rentec.com> wrote:
> When I run
>
> Integrate[1/Pi^2 1/(1 + x^2 + y^2 + z^2)^2, {z, -Infinity, Infinity},
> Assumptions -> {Im[x] == 0, Im[y] == 0, Im[z] == 0}]
>
> I get
> (I*(Log[-(I/Sqrt[1 + x^2 + y^2])] -
> Log[I/Sqrt[1 + x^2 + y^2]]))/
> (2*Pi^2*(1 + x^2 + y^2)^(3/2))
>
> I would like
>
> 1/(2*Pi ) 1/(1 + x^2 + y^2)^3/2
>
> for an answer. How do I get Mathematica to forego the complex
> answer?
>
> thanks, Stewart
>
>
>
>
--
majort at cox-internet.com
Bobby R. Treat
- References:
- Integrate Problem
- From: Stewart Mandell <stewart@rentec.com>
- Integrate Problem