Re: Integrate Problem
- To: mathgroup at smc.vnet.net
- Subject: [mg40672] Re: Integrate Problem
- From: "Dr. Wolfgang Hintze" <weh at snafu.de>
- Date: Sat, 12 Apr 2003 03:14:00 -0400 (EDT)
- References: <200304080705.DAA23549@smc.vnet.net> <b70cga$8a6$1@smc.vnet.net>
- Reply-to: weh at snafu.de
- Sender: owner-wri-mathgroup at wolfram.com
Hi all,
in my version 4.0 even this simpler statement works fine
Integrate[
1/Pi^2 1/(1 + x^2 + y^2 + z^2)^2, {z, -Infinity,
Infinity}] // ComplexExpand
Wolfgang
Dr Bob wrote:
> ComplexExpand@Integrate[1/Pi^2 1/(1 + x^2 + y^2 + z^2)^2,
> {z, -Infinity, Infinity}, Assumptions -> {Im[x] == 0, Im[y] == 0, Im[z] ==
> 0}]
>
> Bobby
>
> On Tue, 8 Apr 2003 03:05:18 -0400 (EDT), Stewart Mandell
> <stewart at rentec.com> wrote:
>
>
>>When I run
>>
>>Integrate[1/Pi^2 1/(1 + x^2 + y^2 + z^2)^2, {z, -Infinity, Infinity},
>>Assumptions -> {Im[x] == 0, Im[y] == 0, Im[z] == 0}]
>>
>>I get
>>(I*(Log[-(I/Sqrt[1 + x^2 + y^2])] -
>>Log[I/Sqrt[1 + x^2 + y^2]]))/
>>(2*Pi^2*(1 + x^2 + y^2)^(3/2))
>>
>>I would like
>>
>>1/(2*Pi ) 1/(1 + x^2 + y^2)^3/2
>>
>>for an answer. How do I get Mathematica to forego the complex
>>answer?
>>
>>thanks, Stewart
>>
>>
>>
>>
>>
>
>
>
- References:
- Integrate Problem
- From: Stewart Mandell <stewart@rentec.com>
- Integrate Problem