Re: Plot of nonlinear function
- To: mathgroup at smc.vnet.net
- Subject: [mg41030] Re: Plot of nonlinear function
- From: "Urijah Kaplan" <uak at sas.upenn.edu>
- Date: Tue, 29 Apr 2003 05:25:57 -0400 (EDT)
- Organization: University of Pennsylvania
- References: <b858i9$5rk$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
I don't think you can solve this is terms of theta2. What you can do instead
is use ImplicitPlot.
<< "Graphics`ImplicitPlot`"
ImplicitPlot[(theta1 - Pi/2)*Sin[theta1 + theta2] -
(theta2 - Pi/2)*(Sin[theta1] +
Sin[theta1 + theta2]) == 0, {theta1, -10, 10},
{theta2, -10, 10}]
Notice the square brackets for the functions, and the capital P in Pi. I
picked -10 to 10 as the domain and range of the graph, you might have had
something different in mind.
--Urijah Kaplan
"Jong Choi" <jxc91 at po.cwru.edu> wrote in message
news:b858i9$5rk$1 at smc.vnet.net...
> Dear all.
> I want to plot this fuction
>
>
(theta1-pi/2)*Sin(theta1+theta2)-(theta2-pi/2)*(Sin(theta1)+Sin(theta1+theta
> 2))=0
>
> This function is non-linear.
> The x axis is theta1 and y axis is theta2
> I think I have to solve this function like, theta2=f(theta1)
> and then plot.
>
> But I have no idea.
> Please give me some idea.
> Thanks,
> Jong Choi
>
>
>
>