Re: Plot of nonlinear function
- To: mathgroup at smc.vnet.net
- Subject: [mg41030] Re: Plot of nonlinear function
- From: "Urijah Kaplan" <uak at sas.upenn.edu>
- Date: Tue, 29 Apr 2003 05:25:57 -0400 (EDT)
- Organization: University of Pennsylvania
- References: <b858i9$5rk$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
I don't think you can solve this is terms of theta2. What you can do instead is use ImplicitPlot. << "Graphics`ImplicitPlot`" ImplicitPlot[(theta1 - Pi/2)*Sin[theta1 + theta2] - (theta2 - Pi/2)*(Sin[theta1] + Sin[theta1 + theta2]) == 0, {theta1, -10, 10}, {theta2, -10, 10}] Notice the square brackets for the functions, and the capital P in Pi. I picked -10 to 10 as the domain and range of the graph, you might have had something different in mind. --Urijah Kaplan "Jong Choi" <jxc91 at po.cwru.edu> wrote in message news:b858i9$5rk$1 at smc.vnet.net... > Dear all. > I want to plot this fuction > > (theta1-pi/2)*Sin(theta1+theta2)-(theta2-pi/2)*(Sin(theta1)+Sin(theta1+theta > 2))=0 > > This function is non-linear. > The x axis is theta1 and y axis is theta2 > I think I have to solve this function like, theta2=f(theta1) > and then plot. > > But I have no idea. > Please give me some idea. > Thanks, > Jong Choi > > > >