Re: Problem
- To: mathgroup at smc.vnet.net
- Subject: [mg43031] Re: [mg42967] Problem
- From: Janak Wedagedera <janak at maths.warwick.ac.uk>
- Date: Sat, 9 Aug 2003 02:57:33 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
Hello,
You can use ImpliciPlot:
<< Graphics`ImplicitPlot`
ImplicitPlot[(x - x^2) + (y - y^2) == c, {x, a, b}]
Case c=0 is straightforward, but need to specify
the corresponding range for c for the real solutions of y.
Eg:
ImplicitPlot[(x - x^2) + (y - y^2) == -1, {x, -1, 1}]
(c=-1).
Is this what you need; sorry if I am wrong.
Best regards
janak.
On Thu, 7 Aug 2003, Andrew Thomas wrote:
> Dear All,
>
> This is a simple one but I cannot find out how to plot the following.
>
> c=(x-x^2)+(y-y^2) where c is a constant.
>
> The problem is that everytime I go to plot the plot is always defined
> as y=f(x,...) and so I cannot enter y^2 into the equation.
>
> Could someone please advise.
>
> Thank you and best wishes,
>
> Andrew
>
>
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------------------------------------
Dr. Janak R Wedagedera
Research Fellow
Mathematics Institute
University of Warwick
Coventry
CV4 7AL
U.K.
e-mail: janak at maths.warwick.ac.uk
janak at maths.ruh.ac.lk
phone: 44 02476 523698 (office)
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