Re: ListPlot3D of a Square Array
- To: mathgroup at smc.vnet.net
- Subject: [mg43076] Re: ListPlot3D of a Square Array
- From: bobhanlon at aol.com (Bob Hanlon)
- Date: Mon, 11 Aug 2003 02:15:55 -0400 (EDT)
- References: <bh4mbg$po4$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Clear[m];
Array[m, {5,5}]
{{m[1, 1], m[1, 2], m[1, 3], m[1, 4], m[1, 5]},
{m[2, 1], m[2, 2], m[2, 3], m[2, 4], m[2, 5]},
{m[3, 1], m[3, 2], m[3, 3], m[3, 4], m[3, 5]},
{m[4, 1], m[4, 2], m[4, 3], m[4, 4], m[4, 5]},
{m[5, 1], m[5, 2], m[5, 3], m[5, 4], m[5, 5]}}
Standing alone (e.g., without being part of a Set statement), the results of an
Array command are transient. Note the definition of m:
?m
Global`m
Whether or not there is anything to plot depends on the <fill up m> commands
that you omitted. Perhaps you intended something like
m=Array[3*#1-5*#2&, {5,5}];
ListPlot3D[m];
Bob Hanlon
In article <bh4mbg$po4$1 at smc.vnet.net>, "Scott Guthery"
<sguthery at mobile-mind.com> wrote:
<< Insight into the following is appreciated:
Array[m, {5,5}]
<fill up m>
ListPlot3D[m]
ListPlot3D grumps that m is not a rectangular
array larger than 2x2.
Looks like it is to me!?!?
>><BR><BR>