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Re: a bug in mathematica 5?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg43253] Re: a bug in mathematica 5?
  • From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
  • Date: Sat, 23 Aug 2003 08:08:27 -0400 (EDT)
  • Organization: Universitaet Leipzig
  • References: <bh2714$hra$1@smc.vnet.net> <200308191153.HAA23522@smc.vnet.net> <bi182l$ad1$1@smc.vnet.net>
  • Reply-to: kuska at informatik.uni-leipzig.de
  • Sender: owner-wri-mathgroup at wolfram.com

Hi,

using a definition like

Hd[B1_?NumericQ, B2_?NumericQ...]=Nintegrate[(Hz-1)^2,{zo,-L/2,L/2}]


will prevent that Mathematica try to evaluate the numerical
approximation
symbolical.

Regards
  Jens

Jason Sidabras wrote:
> 
> I actually joined this mathgroup because I had a question about this.
> I am trying to solve fairly complicated integral problems using FindRoot to
> figure out my coefficients. The code works without an error in 4.2 but in 5
> I get an error about the function not being a real number when z=0 (which is
> one of my integration variables) Basically same error.
> 
> F[x] for me is an NIntegrate of a least of 2 squares over a Region of
> Interest.
> 
> Hd[B1_, B2_...]=Nintegrate[(Hz-1)^2,{zo,-L/2,L/2}]
> Where Hz is a huge expression generated by the number of coeff's and my
> kernel.
> 
> Hopefully this can be resolved because I really would like to use the
> Conjugate Gradient Method built into FindRoot on 5.
> 
> I didnt notice the {x,{x0,x1}} change in the doc but thats not a real
> problem.
> 
> Hopefully this can get resolved with a simple patch.
> 
> Jason


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