Re: Maybe it's me but the integrator at wolfram doesn't work very well
- To: mathgroup at smc.vnet.net
- Subject: [mg44978] Re: Maybe it's me but the integrator at wolfram doesn't work very well
- From: bobhanlon at aol.com (Bob Hanlon)
- Date: Fri, 12 Dec 2003 04:41:14 -0500 (EST)
- References: <br9i4v$d22$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
The Integrator works fine on this problem. ln x is not Log[x] it is x times a variable named ln that is assumed to be independent of x Enter the expression as 1/x Log[x] Bob Hanlon In article <br9i4v$d22$1 at smc.vnet.net>, geoman <geogeo9090 at yahoo.com> wrote: << Firstly the "integrator" tool at wolfram evaluates the indefinite integral. Fine Here are some examples of incorrect answers of the "integrator" INT means the integral sign INT 1 / x ln x Don't feel bad though I found another site at mss.vanderbilt.edu that got it wrong as well Now this is quite a fundamental integral but is it hopelessly botched by the "integrator." Here is another INT ln x the "integrator" got that wrong as well. I did find a site that got it right though. Where the error lies I don't know but do in fact think it may be somewhere in the original mathematica code. BTW can anyone on this list give me the correct answers to the above thanks geo.