Re: Replacement rules with I (sqrt(-1)
- To: mathgroup at smc.vnet.net
- Subject: [mg45236] Re: Replacement rules with I (sqrt(-1)
- From: "John Doty" <jpd at w-d.org>
- Date: Tue, 23 Dec 2003 05:13:29 -0500 (EST)
- References: <brhi2e$jha$1@smc.vnet.net> <brk4oe$sq7$1@smc.vnet.net> <brpkil$7m4$1@smc.vnet.net> <brs4nf$ihe$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
In article <brs4nf$ihe$1 at smc.vnet.net>, "Jean.Pellegri" <Jean.Pellegri at wanadoo.fr> wrote: > Is \[ImaginaryI] an "atom" (or "symbol") (like 3 or like a) ?? \[ImaginaryI] is a letter. It may be part of a symbol. There is a built-in symbol whose name is just \[ImaginaryI]. This particular symbol evaluates to Complex[0,1]. > > Is not Complex[3,1] an "atom" ?? It is an atom, but it is not a symbol. -- | John Doty "You can't confuse me, that's my job." | Home: jpd at w-d.org | Work: jpd at space.mit.edu