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Re: Integration of Exp[-x^2]/(1 + Exp[a * x])


Perhaps the simple explanation is that there is no closed form for the
indefinite integral.

Tomas Garza
Mexico City
----- Original Message -----
From: "Stefan" <themailingman at yahoo.de>
To: mathgroup at smc.vnet.net
Subject: [mg39649] [mg39623] Integration of Exp[-x^2]/(1 + Exp[a * x])


> Hello,
>
>
>
> I have to integrate the function Exp[-x^2]/(1 + Exp[a * x]) where a is
> real-valued parameter. Unfortunately
>
>
>
> Integrate[Exp[-x^2]/(1 + Exp[a * x]), x]
>
>
>
> yields no results. Does anyone know a clever trick I might have missed?
Any
> hint would be welcome,
>
>
> Thanks in advance, Stefan
>
>
>
>
>




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