Re: Re: Integration of Exp[-x^2]/(1 + Exp[a * x])

*To*: mathgroup at smc.vnet.net*Subject*: [mg39665] Re: [mg39638] Re: Integration of Exp[-x^2]/(1 + Exp[a * x])*From*: Dr Bob <drbob at bigfoot.com>*Date*: Fri, 28 Feb 2003 04:45:39 -0500 (EST)*References*: <b3hs7u$iki$1@smc.vnet.net> <200302270527.AAA24373@smc.vnet.net>*Reply-to*: drbob at bigfoot.com*Sender*: owner-wri-mathgroup at wolfram.com

>> with your exact input (copy and paste) I get.... No, you didn't. There was no variable "x2" in Stefan's input, as there is in your output. You left out a "^" in his input. Bobby On Thu, 27 Feb 2003 00:27:30 -0500 (EST), Marc Noël <marc.noel at skynet.be> wrote: > with your exact input (copy and paste) I get > \!\(\[ExponentialE]\^\(-x2\)\ \((x - > Log[1 + \[ExponentialE]\^\(a\ x\)]\/a)\)\) > it just works fine, > > did you push shift return or enter to get the evaluation done > > marc > > Stefan a écrit: >> Hello, >> >> >> >> I have to integrate the function Exp[-x^2]/(1 + Exp[a * x]) where a is >> real-valued parameter. Unfortunately >> >> >> >> Integrate[Exp[-x^2]/(1 + Exp[a * x]), x] >> >> >> >> yields no results. Does anyone know a clever trick I might have missed? >> Any >> hint would be welcome, >> >> >> Thanks in advance, Stefan >> >> >> >> > > > -- majort at cox-internet.com Bobby R. Treat

**References**:**Re: Integration of Exp[-x^2]/(1 + Exp[a * x])***From:*Marc Noël <marc.noel@skynet.be>