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MathGroup Archive 2003

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Re: Re: Integration of Exp[-x^2]/(1 + Exp[a * x])

  • To: mathgroup at smc.vnet.net
  • Subject: [mg39665] Re: [mg39638] Re: Integration of Exp[-x^2]/(1 + Exp[a * x])
  • From: Dr Bob <drbob at bigfoot.com>
  • Date: Fri, 28 Feb 2003 04:45:39 -0500 (EST)
  • References: <b3hs7u$iki$1@smc.vnet.net> <200302270527.AAA24373@smc.vnet.net>
  • Reply-to: drbob at bigfoot.com
  • Sender: owner-wri-mathgroup at wolfram.com

>> with your exact input (copy and paste) I get....

No, you didn't. There was no variable "x2" in Stefan's input, as there is 
in your output.  You left out a "^" in his input.

Bobby

On Thu, 27 Feb 2003 00:27:30 -0500 (EST), Marc Noël <marc.noel at skynet.be> 
wrote:

> with your exact input (copy and paste) I get
> \!\(\[ExponentialE]\^\(-x2\)\ \((x -
> Log[1 + \[ExponentialE]\^\(a\ x\)]\/a)\)\)
> it just works fine,
>
> did you push shift return or enter to get the  evaluation done
>
> marc
>
> Stefan a écrit:
>> Hello,
>>
>>
>>
>> I have to integrate the function Exp[-x^2]/(1 + Exp[a * x]) where a is
>> real-valued parameter. Unfortunately
>>
>>
>>
>> Integrate[Exp[-x^2]/(1 + Exp[a * x]), x]
>>
>>
>>
>> yields no results. Does anyone know a clever trick I might have missed? 
>> Any
>> hint would be welcome,
>>
>>
>> Thanks in advance, Stefan
>>
>>
>>
>>
>
>
>



-- 
majort at cox-internet.com
Bobby R. Treat



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