Re: Derivative help
- To: mathgroup at smc.vnet.net
- Subject: [mg39156] Re: [mg39139] Derivative help
- From: Dr Bob <drbob at bigfoot.com>
- Date: Fri, 31 Jan 2003 19:57:08 -0500 (EST)
- References: <200301310936.EAA07518@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
You really are new to Mathematica. Parentheses are used for grouping, but square brackets are used for function arguments, and the Log function is, well, Log. Also, the way you entered f, it would be an expression, but not a function (since you don't say what its argument is, or that it has an argument). Here are a few ways to do it: f = Log[#]^# & f'[x] Log[#1]^#1 & Log[x]^x*(1/Log[x] + Log[Log[x]]) or D[Log[x]^x, x] Log[x]^x*(1/Log[x] + Log[Log[x]]) or f = Log[x]^x D[f, x] Log[x]^x*(1/Log[x] + Log[Log[x]]) Bobby On Fri, 31 Jan 2003 04:36:46 -0500 (EST), Steve Chiang <stevezx at attbi.com> wrote: > Hi, all. I'm new to Mathematica. I went to the help section for my > question but it only further confused me. I'm basically trying to take > the > first derivative of (ln(x))^x. Here is my syntax: f = (ln(x))^x. But > then > when I evaluate f ', it says nothing but ((ln(x))^x)' which is nothing > new. > Is this because I didn't specify bounds and that the function may be > discontinuous over the default bounds in Mathematica? > > Thanks > > > -- majort at cox-internet.com Bobby R. Treat
- References:
- Derivative help
- From: "Steve Chiang" <stevezx@attbi.com>
- Derivative help