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Re: plotting of curve

  • To: mathgroup at smc.vnet.net
  • Subject: [mg42157] Re: plotting of curve
  • From: gohtk at rocketmail.com (goh tat kean)
  • Date: Sat, 21 Jun 2003 02:49:34 -0400 (EDT)
  • References: <bcuiaf$2p9$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Dear Kee,

I am not sure whether I understand your question correctly. What I
think are given as below:

You have an equation of 2*Exp[1/(Wx)]/(587 - x)^2,

I rewrite it as 

y = 2*Exp[1/(w x)]/(587 - x)^2

You mentioned w = 5.8 and you want to plot the generated equation as y
against 1/(w x),

w = 5.8;

Create a table comprises of 1/(w x) and y (your equation),

list1 = Table[{1/(w x), y}, {x, 1, 20}];

Plot the values,

p1=ListPlot[list1];

Hope this can help. Good luck!

Regards,
tat kean

ce.choa.phen.kee at philips.com wrote in message news:<bcuiaf$2p9$1 at smc.vnet.net>...
> Hi all,
> 
> May I know how can I plot this equation 2*Exp[1/(Wx)]/(587 - x)^2 which I have gotten from
> this function: NonlinearFit[values, (MM * Exp[1/Wx])/(NN-x)^2, 
> {x,1/(Wx)},{{MM,5},{NN,600}}]? 
> 
> I made use of x-values and 1/(Wx) values to fit the data into the desired 
> equations. But just have no idea on how to plot the generated equation as y against 1/(Wx). 
> 
> Given W is 5.8 and the two x in the equation are both using the same 
> x-values..
> 
> pls guide..
> 
> Thanks in advance.
> 
> regards,
> kee


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