Re: plotting of curve
- To: mathgroup at smc.vnet.net
- Subject: [mg42153] Re: plotting of curve
- From: Mark Westwood <MarkCWestwood at compuserve.com>
- Date: Sat, 21 Jun 2003 02:49:31 -0400 (EDT)
- References: <bcuiaf$2p9$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Kee,
A simple answer is:
Plot[2*Exp[1/(W x)]/(587 - x)^2/.W->5.8, {x,-10,10}]
Note:
--- W x is written with a space between the letters, which causes
Mathematica to understand that the variables should be multiplied;
--- /.W->5.8 is a replacement rule, which sets the value of W to be 5.8
within the scope of the Plot command, but does not change it outside the
scope of the command;
--- set the min and max values for x to whatever you wish. Note that
the function is undefined when x==0, which might cause Mathematica to
generate a warning message, but should not prevent it having a stab at
drawing the graph.
Hope this helps
Mark Westwood
ce.choa.phen.kee at philips.com wrote:
>
> Hi all,
>
> May I know how can I plot this equation 2*Exp[1/(Wx)]/(587 - x)^2 which I have gotten from
> this function: NonlinearFit[values, (MM * Exp[1/Wx])/(NN-x)^2,
> {x,1/(Wx)},{{MM,5},{NN,600}}]?
>
> I made use of x-values and 1/(Wx) values to fit the data into the desired
> equations. But just have no idea on how to plot the generated equation as y against 1/(Wx).
>
> Given W is 5.8 and the two x in the equation are both using the same
> x-values..
>
> pls guide..
>
> Thanks in advance.
>
> regards,
> kee