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Re: plotting of curve

  • To: mathgroup at smc.vnet.net
  • Subject: [mg42153] Re: plotting of curve
  • From: Mark Westwood <MarkCWestwood at compuserve.com>
  • Date: Sat, 21 Jun 2003 02:49:31 -0400 (EDT)
  • References: <bcuiaf$2p9$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

Kee,

A simple answer is:

Plot[2*Exp[1/(W x)]/(587 - x)^2/.W->5.8, {x,-10,10}]

Note: 

--- W x is written with a space between the letters, which causes
Mathematica to understand that the variables should be multiplied;
--- /.W->5.8 is a replacement rule, which sets the value of W to be 5.8
within the scope of the Plot command, but does not change it outside the
scope of the command;
--- set the min and max values for x to whatever you wish.  Note that
the function is undefined when x==0, which might cause Mathematica to
generate a warning message, but should not prevent it having a stab at
drawing the graph.

Hope this helps
Mark Westwood





ce.choa.phen.kee at philips.com wrote:
> 
> Hi all,
> 
> May I know how can I plot this equation 2*Exp[1/(Wx)]/(587 - x)^2 which I have gotten from
> this function: NonlinearFit[values, (MM * Exp[1/Wx])/(NN-x)^2,
> {x,1/(Wx)},{{MM,5},{NN,600}}]?
> 
> I made use of x-values and 1/(Wx) values to fit the data into the desired
> equations. But just have no idea on how to plot the generated equation as y against 1/(Wx).
> 
> Given W is 5.8 and the two x in the equation are both using the same
> x-values..
> 
> pls guide..
> 
> Thanks in advance.
> 
> regards,
> kee


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