MathGroup Archive: March 2003 [00185]

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AW: Desciphering Solve[] output.

To: mathgroup at smc.vnet.net
Subject: [mg39813] AW: [mg39763] Desciphering Solve[] output.
From: Matthias.Bode at oppenheim.de
Date: Sat, 8 Mar 2003 02:46:08 -0500 (EST)
Sender: owner-wri-mathgroup at wolfram.com

Hello Ryan,

try:
1*1
and
1.0*1

and have a look at THE BOOK:

3.1.3 Converting between Different Forms of Numbers

Best regards,
Matthias Bode
Sal. Oppenheim jr. & Cie. KGaA
Koenigsberger Strasse 29
D-60487 Frankfurt am Main
GERMANY
Tel.: +49(0)69 71 34 53 80
Mobile: +49(0)172 6 74 95 77
Fax: +49(0)69 71 34 95 380
E-mail: matthias.bode at oppenheim.de
Internet: http://www.oppenheim.de



-----UrsprÃ¼ngliche Nachricht-----
Von: rhaldimann at hotmail.com [mailto:rhaldimann at hotmail.com]
Gesendet: Donnerstag, 6. MÃ¤rz 2003 08:36
An: mathgroup at smc.vnet.net
Betreff: [mg39763] Desciphering Solve[] output.


Solve posts some funny parameters when i solve a set of 6 simultaneous eqns.
eg.

x1 == 1.*(X - 1.*Bx*Cos(\[Psi]) + Bz*Cos(\[Psi])*Cot(B)*Sec(A) - 
        1.*UFly*Cos(A)*
          Sin(B) + (1.*Bz*m1*Cos(B)*Cos(\[Psi]))/(1.*Cos(A)*Cos(B) - 
              1.*m1*Cos(A)*Sin(B)) + (1.*Bx*Cos(A)*Cos(B)*
              Cos(\[Psi]))/(1.*Cos(A)*Cos(B) - 1.*m1*Cos(A)*Sin(B)) +
(1.*b1*
              Cos(A)*Sin(B))/(1.*Cos(A)*Cos(B) - 1.*m1*Cos(A)*Sin(B)) +
(1.*....

what does the 1. mean????? I also occasionally get a 0. 

many thanks,
Ryan H

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