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MathGroup Archive 2003

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Re: Plot a recurrence relation

  • To: mathgroup at smc.vnet.net
  • Subject: [mg40171] Re: Plot a recurrence relation
  • From: atelesforos at hotmail.com (Orestis Vantzos)
  • Date: Tue, 25 Mar 2003 03:02:05 -0500 (EST)
  • References: <b5mj14$rsa$1@smc.vnet.net>
  • Sender: owner-wri-mathgroup at wolfram.com

a[0]=6;
a[n_]:=(a[n]=a[n-1]/(2n-9));
ListPlot[Array[a,{100},{0}]]

will plot the first 100 terms.

Notice that the definition a[n_]:=a[n]=... stores the value of the
n-th term for efficiency (dynamic programming).
Clear[a] will clear the stored values(and the defintion).

Orestis

"David" <davidol at hushmail.com> wrote in message news:<b5mj14$rsa$1 at smc.vnet.net>...
> How can I get mathematica to plot a sequence that's defined recursively e.g.
> 
> a_0 = 6
> a_(n+1) = a_n / (2n - 7)
> 
> Cheers.


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