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Re: Plot a recurrence relation


Here is some code to calculate it

a[0]=6;
a[n_]:=a[n]=a[n-1]/(2n-9)
TableForm[tbl=Table[{n,a[n]},{n,0,10}]]
ListPlot[tbl];

The construct a[n_]:=a[n]=... keeps a[n] in memory after the first time it
is called so that you do not recacluate all of the a[n] each time.

Kevin

"David" <davidol at hushmail.com> wrote in message
news:b5mj14$rsa$1 at smc.vnet.net...
> How can I get mathematica to plot a sequence that's defined recursively
e.g.
>
> a_0 = 6
> a_(n+1) = a_n / (2n - 7)
>
> Cheers.
>
>
>




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