Re: Plot a recurrence relation

*To*: mathgroup at smc.vnet.net*Subject*: [mg40165] Re: Plot a recurrence relation*From*: "Kevin J. McCann" <kjm@KevinMcCann>*Date*: Tue, 25 Mar 2003 03:01:33 -0500 (EST)*References*: <b5mj14$rsa$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Here is some code to calculate it a[0]=6; a[n_]:=a[n]=a[n-1]/(2n-9) TableForm[tbl=Table[{n,a[n]},{n,0,10}]] ListPlot[tbl]; The construct a[n_]:=a[n]=... keeps a[n] in memory after the first time it is called so that you do not recacluate all of the a[n] each time. Kevin "David" <davidol at hushmail.com> wrote in message news:b5mj14$rsa$1 at smc.vnet.net... > How can I get mathematica to plot a sequence that's defined recursively e.g. > > a_0 = 6 > a_(n+1) = a_n / (2n - 7) > > Cheers. > > >