Re: about real part
- To: mathgroup at smc.vnet.net
- Subject: [mg41210] Re: about real part
- From: "Dr. Wolfgang Hintze" <weh at snafu.de>
- Date: Wed, 7 May 2003 03:57:33 -0400 (EDT)
- References: <b982nm$67m$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
You can even simplify the problem thus In[1] = Re[Sqrt[a + I ]] leading "at most" (using //ComplexExpand) to Out[1] = Sqrt[Abs[I + a] * Cos[1/2 Arg[I + a]] If you assign a value to a, say a=1 then the result is ok, viz. 2^(1/4) * Cos[Pi/8] But in general one would expect something like (1+a*a)^(1/4) * Sqrt[(1 + a/Sqrt(1+a*a)) / 2] I couldn't find that expression using Mathematica's Simplifying means. Regards, Wolfgang Duanxiang Xu wrote: > Hi, all > > I have problem when I was trying to get the real part > of a complex expression, > like > Re[(Iwt+(L+1)LtD)^1/2] > here w,L,D are real paramaters and t is real variable > Mathematica seems could do nothing about this > > Anyone could help me? > > Thanks, > Duanxiang > > __________________________________ > Do you Yahoo!? > The New Yahoo! Search - Faster. Easier. Bingo. > http://search.yahoo.com > >