Re: Re: Q
- To: mathgroup at smc.vnet.net
- Subject: [mg41485] Re: [mg41478] Re: Q
- From: Selwyn Hollis <selwynh at earthlink.net>
- Date: Thu, 22 May 2003 06:54:03 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
Paul, that's amazing! Please give us an explanation of how that works.
Regards,
Selwyn
On Wednesday, May 21, 2003, at 08:04 AM, Paul Abbott wrote:
> The following code determines the f'[0],..., Derivative[m][f][0] in
> terms of f[0] as replacement rules (which is usually better than
> assigning them as numerical values):
>
> m=4;
>
> Solve[f'[t] - g[f[t]] + O[t]^m == 0,
> Table[Derivative[n][f][0], {n, m}]]