Re: Declaring a variable real
- To: mathgroup at smc.vnet.net
- Subject: [mg41641] Re: Declaring a variable real
- From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
- Date: Thu, 29 May 2003 08:14:11 -0400 (EDT)
- Organization: Universitaet Leipzig
- References: <bb1v5g$9h7$1@smc.vnet.net>
- Reply-to: kuska at informatik.uni-leipzig.de
- Sender: owner-wri-mathgroup at wolfram.com
Hi, have a look to the Assumptions option of Integrate[] you can specify there that Element[s,Reals] Regards Jens M wrote: > > I'm integrating a function. Mathematica gives a conditional output: > computing the integral > if Re[s^2]>0 and leaving the integral undone otherwise (s is a parameter in > the integrand). I'd like to tell mathematica that s is real valued so it > just generates the integral instead of giving me a conditional statement. I > tried doing a Simplify on the integral placing the constraint that s > belonged to the set of Reals. It had no effect. Apparently the Simplify[..] > command cannot simplify a conditional statement? > Help