Re: Declaring a variable real
- To: mathgroup at smc.vnet.net
- Subject: [mg41622] Re: Declaring a variable real
- From: Peter Breitfeld <phbrf at t-online.de>
- Date: Thu, 29 May 2003 08:13:47 -0400 (EDT)
- References: <bb1v5g$9h7$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
M schrieb: > I'm integrating a function. Mathematica gives a conditional output: > computing the integral > if Re[s^2]>0 and leaving the integral undone otherwise (s is a parameter in > the integrand). I'd like to tell mathematica that s is real valued so it > just generates the integral instead of giving me a conditional statement. I > tried doing a Simplify on the integral placing the constraint that s > belonged to the set of Reals. It had no effect. Apparently the Simplify[..] > command cannot simplify a conditional statement? > Help > Use the option Assumptions of Integrate Gruß Peter -- =--=--=--=--=--=--=--=--=--=--=--=--=--= http://home.t-online.de/home/phbrf Peter Breitfeld, Bad Saulgau, Germany Meinen GnuPG/PGP-5x Key gibts dort