Re: Bug 3! Gaussian integration in 5.0 is broken!

*To*: mathgroup at smc.vnet.net*Subject*: [mg43816] Re: Bug 3! Gaussian integration in 5.0 is broken!*From*: Konstantin L Kouptsov <kouptsov at wsu.edu>*Date*: Tue, 7 Oct 2003 02:40:55 -0400 (EDT)*Organization*: Washington State University*References*: <blj66o$1i8$1@smc.vnet.net> <bllo8p$bsh$1@smc.vnet.net>*Sender*: owner-wri-mathgroup at wolfram.com

Indeed works. But as you can see, it does not generate the message that convergence cannot be checked. Thus, in this case Mathematica chooses a different evaluation route (using different rules), and avoids the one that is broken. Thanks for the hint. Konstantin. Paul Abbott wrote: > In article <blj66o$1i8$1 at smc.vnet.net>, > Konstantin L Kouptsov <kouptsov at wsu.edu> wrote: > > >>Check this: >> >>Integrate[Exp[(I/h)*(x*Sqrt[B/2 + D] + x0)^2], {x, -Infinity, Infinity}] >> >>and observe the Erf[] functions that should not be there. Neither should x0. > > > However, note the assumptions that Integrate makes. On the other hand, > > Assuming[x0 > 0 && B > 0 && D > 0 && h > 0, > Integrate[E^((I*(Sqrt[B/2 + D]*x + x0)^2)/h), > {x, -Infinity, Infinity}]] > > yields a reasonable result. > > Cheers, > Paul >